Cy232023-01-20 来自辽宁看了下同学的留言学习了下，并改写正则，使其捕获单词排除换行和空格等 改写如下： from re import findall from collections import Counter with open('./demo1.txt', 'r') as f: data = f.read().lower() words = findall(r'\b\w*?\S\b', data) print(Counter(words)) print(Counter(words).most_common(5))作者回复: 赞，不断迭代代码是正确提高编程能力的有效方式
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谢韬 Fragos2023-03-01 来自北京如老师提到如果需要累加多个点，比如p1+p2+p3+p4有下面三种方法供大家参考： 第一种方法：在__add__方法中返回Point_2D的类型，而不是tuple。 from collections import namedtuple class Point_2D (namedtuple('Point',['x','y'])): def __add__(self,other): self.other_x, self.other_y= other return self.__class__(self.x+self.other_x,self.y+self.other_y) p1= Point_2D(x=11,y=22) p2 = Point_2D(x=33,y=44) p3 = Point_2D(x=55,y=66) p4 = Point_2D(x=77,y=88) p1+p2+p3+p4 #第二种方法：重载Point_2D的__radd__方法，否则它会以元组的默认加法方式进行。 from collections import namedtuple class Point_2D(namedtuple('Point',['x','y'])): def __add__(self,other): self.other_x , self.other_y = other return self.x + self.other_x, self.y+ self.other_y def __radd__(self,other): self.other_x , self.other_y = other return self.x + self.other_x, self.y+ self.other_y #第三种方法：这段代码还是不够pythonic，__add__和__radd__代码重复了，如果连个方法的表现出一样的行为直接用=就可以了。 from collections import namedtuple class Point_2D(namedtuple('Point',['x','y'])): def __add__(self,other): self.other_x,self.other_y =other return self.x + self.other_x,self.y + self.other_y __radd__=__add__展开作者回复: 送你上去~
PatrickL2023-01-16 来自上海import re from collections import Counter with open('hamlet.txt','r') as f: data = f.read().lower() words = re.findall(r'\w+', data) print(Counter(words).most_common(5))1
Geek_Mike2023-08-14 来自云南# 自定义命名元组的加法和减法功能 from collections import namedtuple Point = namedtuple('Point', ['x', 'y']) def add(self, other): return self.x + other.x, self.y + other.y Point.__add__ = add def subtract(self, other): return self.x - other.x, self.y - other.y Point.__sub__ = subtract p1 = Point(2, 3) p2 = Point(1, 4) print(p1 + p2) print(p1 - p2)- Geek_Mike2023-08-14 来自云南# 统计一篇文章中出现频率在前五的单词，并将单词和出现次数一起输出到终端 from collections import Counter import re words = re.findall(r'\w+', open('./demo.txt').read()) print(Counter(words).most_common(5)) >>>[('Python', 12), ('3', 12), ('10', 12), ('11', 6), ('is', 6)]
Greenery2023-07-24 来自中国香港from re import findall with open('demo.txt',encoding='UTF-8') as f: cnt=f.read() c=Counter(findall(r'\w+',cnt)) c.most_common(5)
Mr.Cui2023-05-23 来自浙江# 请你编写程序，统计一篇文章中出现频率在前五的单词，并将单词和出现次数一起输出到终端。 # 使用 collections容器数据类型中的 Counter 对象 from collections import Counter with open('./case.log',mode='r') as f: content = f.read().lower() for word, count in Counter(content.split()).most_common(5): print(f"{word}: {count}")
江江儿嘛哩哄2023-03-08 来自浙江from collections import Counter import re words = re.findall(r'\w+', open('a.txt').read().lower()) print(Counter(words).most_common(5))
yanyu-xin2023-02-27 来自广东from collections import Counter import re words = re.findall(r'\w+', open('E4.txt',encoding='UTF-8').read().lower()) print(Counter(words).most_common(5))
朱雯2023-02-04 来自北京from re import findall from collections import Counter with open('./demo1.txt', 'r') as f: data = f.read().lower() words = findall(r'\b\w*?\S\b', data) print(Counter(words)) print(Counter(words).most_common(5))