这个报错是因为什么： HTTPError: HTTP Error 405: METHOD NOT ALLOWED 我应该是python 3.7 详细的代码: data = bytes(parse.urlencode({'word':'hello'}),encoding='utf8') # 封装数据 # print(data) response = request.urlopen('http://httpbin.org/post', data=data) print(response.read().decode('utf-8')) 结果 HTTPError Traceback (most recent call last) <ipython-input-7-d499555bfa10> in <module> 2 # print(data) 3 ----> 4 response = request.urlopen('http://httpbin.org/post', data=data) 5 print(response.read().decode('utf-8')) （中间省略了） ~\Anaconda3\lib\urllib\request.py in http_error_default(self, req, fp, code, msg, hdrs) 647 class HTTPDefaultErrorHandler(BaseHandler): 648 def http_error_default(self, req, fp, code, msg, hdrs): --> 649 raise HTTPError(req.full_url, code, msg, hdrs, fp) 650 651 class HTTPRedirectHandler(BaseHandler): HTTPError: HTTP Error 405: METHOD NOT ALLOWED

设置timeout=0.1时的报错是socket.timeout: timed out而非urllib.error.URLError，那还是这样写吗？ try: response3=urllib.request.urlopen('http://httpbin.org/get',timeout=1) except urllib.error.URLError as e: if isinstance(e.reason,socket.timeout): print('TIME OUT') 这样写try之后还是报错socket.timeout: timed out

老师,我的环境使用request.urlopen()后没有.read()方法，大概什么原因啊

老师，我在if里面有 if isinstance(e.reason, socket.timeout):， 但run的时候还是没捕捉到异常，提示 socket.timeout: timed out

老师您好： 按照例子里的写法还是会出异常 是因为python版本的问题吗？ python 3.6.7 try:     response3 = urllib.request.urlopen('http://httpbin.org/get', timeout=0.1) except urllib.error.URLError as e:     if isinstance(e.reason, socket.timeout):         print('TIME OUT') 但是改成这样后就不会了 except socket.timeout as e:     print(e) 因为这样捕获的输出结果是 <class 'socket.timeout'> except Exception as e:     print(type(e))

http网页越来越少了，现在https更多

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